Maths Problem?

1 ⤊

Find a in terms of b, given that :
Log[base 2] (a*b^2) = 3
Anyone knowhow to do this ?

2007-05-02 21:35:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

Log[base 2] (a*b^2) = 3

Get rid of the log

a*b^2 = 2^3 = 8

a = 8/(b^2)

2007-05-02 21:39:49 · answer #1 · answered by dudara 4 · 1⤊ 0⤋

Log[base 2] (a*b^2) = 3

Log[base 2] (a*b^2) = 3

so,a*b^2 = 2^3 = 8

so,a = 8/(b^2)

2007-05-03 04:43:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋

log_2 (ab^2) = 3
<=> ab^2 = 2^3 = 8
<=> a = 8/b^2.

2007-05-03 04:39:50 · answer #3 · answered by Scarlet Manuka 7 · 0⤊ 0⤋