Can somebody PLEASE help me with this math!!!?

Question

Inga is starting a new rectangular garden. She wants the length to be 3 times the width, and she has 56 meters of fencing to put around the garden. Use the system of equations listed below to find the length "L" and width "W" of the garden. 2L+2W=56 and L=3W

is it:
a. W=21, L=7
b.W=3, L=7
c.W=7, L=21
d.W=3, L=21

Answer 1

might want to check my math...I get 'c'
x=width
3x=length
a rectangular garden has 4 sides (2 w-sides and 2 l-sides)
therefore
2(x) +2(3x) = 56
2x + 6x = 56
8x = 56
x = 56 divided by 8
x = 7
This gives you a width of 7.
The length being 3 times the width = 3(7) = 21
CHECK:
2(x) + 2(3x) = 56
2(7) + 2[(3)(7)] =56
14 + 2(21) = 56
14 + 42 = 56
56 =56

Answer 2

2L + 2W = 56 (equation 1)
L = 3W (equation 2)

Substitute L = 3W in equation 1 to get
2(3W) + 2W = 56
6W + 2W = 56
8W = 56
So W = 7

Substitute W = 7 in equation 2 to get
L = 3(7)
So L = 21

To check your answer substitute L = 21 and W = 7 in equation one
2L + 2W = 56
2(21) + 2(7) = 56
42 + 14 = 56
56 = 56

So the answer is choice C

Answer 3

just plug in L=3W into the first equation..

so 2(3W)+2W=56 then solve for W

6W+2W=56
8W=56
W=7

now that you know W you can find L by plugging in W to the second equation.

L=3(7)
L=21

Math is fun!!

Answer 4

It's choice a. To solve it, solve the 2nd equation for w (w=L/3). Then plug this into the first equation. You will get L=21. Then plug this value into the first equation to get W=7.

Answer 5

2L+2W=56 L=3W
2(3W)+2W=56
6W+2W=56
8W=56
W=56/8
W=7

2L+2W=56
2L+2(7)=56
2L+14=56
2L=56-14
2L=42
L=42/2
L=21

Answer 6

the ans is c. w=7 and l=21

Answer 7

c.W=7, L=21

Answer 8

2L+2W=56 ..........................a
L=3W => L-3W=0................b
multiplying b by 2 gives:-
2L-6W=0.................................b
a-b gives:-
8W=56 => W=7
putting valuue of W in eq. b give:-
L=3(7)=21
sooooooo option c is correct

Answer 9

2L + 2W = 56
6W + 2W = 56
8W = 56
W = 7
L = 21
Answer c)

Answer 10

2W +2(3W)=56
8W=56
W=7

L=3*7
L=21

Ans:C