Find the length of the following segment created by these pairs of endpoints: (1, 1), (-3, 6)
36
41
4.6
6.4
2007-05-02 18:29:36 · 5 answers · asked by milla q 1 in Science & Mathematics ➔ Mathematics
6.4
2007-05-02 18:51:51 · answer #1 · answered by Afternoon Delight 4 · 0⤊ 0⤋
L² = (- 3 - 1)² + (6 - 1)²
L² = 16 + 25
L = â41
2007-05-03 06:50:57 · answer #2 · answered by Como 7 · 0⤊ 0⤋
Not sure if I did this right but I get 8.1(rounded).
If you draw out (1,1),(-3,6) on a grid. you get
[draw the two points, draw a line to connect them, draw a vertical line along (-3,6) and a horizontal line along (1,1)...this will give you a visual aide of the triangle...count off the spacings to get the numbers below.
SideA (verticle)=4 [4 spaces between (-3,6) to where the horizontal line crosses through the vertical line]
SideB (horizontal)=7 [7 spaces between (1,1) to where the vertical line intersects the horizontal one]
Angle between=90 degrees (for if you use another formula)
a^2 + b^2 = c^2
(4)^2 + (7)^2 = c^2
(16) + (49) = c^2
65 = c^2
sq root of 65 = 8.1 (rounded)
If I did this wrong...sorry
There's also a calculator at this link...used it to check my figures...http://ostermiller.org/calc/triangle.html
2007-05-03 01:59:49 · answer #3 · answered by mimi 3 · 0⤊ 0⤋
s = â((x1 - x0)^2 + (y1 - y0)^2)
s = â((-3 - 1)^2 + (6 - 1)^2)
2007-05-03 01:37:48 · answer #4 · answered by Helmut 7 · 0⤊ 0⤋
6.4
HTH
Doug
2007-05-03 01:38:03 · answer #5 · answered by doug_donaghue 7 · 0⤊ 0⤋