2.00 L of a gas is collected at 25*C and 745.0 mm Hg. What is the volume at STP?

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2.00 L of a gas is collected at 25*C and 745.0 mm Hg. What is the volume at STP?

I can set it up on the formula but im having trouble solving it, show me how to solve it please.

2007-05-02 18:07:53 · 3 answers · asked by Oscar 1 in Science & Mathematics ➔ Chemistry

3 answers

2 x 273/298 x 745/760

2007-05-02 19:40:20 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋

V at STP = (745*2*273)/(298*760) l

2007-05-02 19:47:05 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋

The mathematical form of the mixed gas regulation is: P1 x V1 / T1 = P2 x V2 / T2 whilst any 5 of the six parts interior the equation are popular, the 6th may well be calculated. Unit Conversions: P1 = 720.mmHg / 760 mmHg x a million.000 atm = 0.947 atm T1 = 25C + 273.15 = 298 °ok very final Calculations: V2 = P1V1T2/P2T1 = 0.947 atm x a million.fifty 5 L x 2.73x102 °ok / (a million. atm x 298 °ok) = a million. L

2016-12-10 17:57:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋