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in the chapter electrochemistry... i learnt that ions in the lower position of the electrochemical series will be discharged. but if the concentration of another ion is high, then the ions will be discharge. e.g. concentration lead(ll) sulphate solution. Pb2+ will be discharged althouh H+ is lower than Pb2+. then how about dilute copper(ll) suphate solution? the H+ is more concentrated and Cu2+ is diluted but Cu2+ is lower than H+. which ion will be discharged first? Cu2+ or H+?

2007-05-02 17:41:16 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

Unless the solution is acidified, the [Cu2+] concentration is much, much greater than the [H+] concentration, so Cu2+ ions will be discharged.

2007-05-02 19:42:32 · answer #1 · answered by Gervald F 7 · 0 0

Cu2+.

2007-05-03 02:47:10 · answer #2 · answered by ag_iitkgp 7 · 0 0

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