multiply 4y^ (y+1) (y-1)?

2007-05-02 17:07:33 · 2 answers · asked by deborah n 1 in Science & Mathematics ➔ Mathematics

What should the power be on the y^?

2007-05-02 17:28:12 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋

Assuming that you meant ...
4 * y^((y+1)(y-1)) , which would
= 4 * y^(y^2 +y -y -1)
= 4 * y^(y^2 -1)
= 4 * y^(y^2) / y

2007-05-02 17:51:53 · answer #2 · answered by Truly W 5 · 0⤊ 0⤋

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