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My final is tomorrow so I am freaking out! Anyway I I need to set this up as an Empirical formula:
When 1.00g of metallic Chromium is heated with element Chlorine gas, 3.045g of chromium salt results. Thank you!

2007-05-02 16:55:21 · 4 answers · asked by Anonymous in Science & Mathematics Chemistry

4 answers

1)Convert the mass of each element to moles: 1gCr * 1mol/52gCr=0.019molCr
3.045gCl *1mol/35.45gCl=0.086molCl

2) use the answers as a subscript for each element: Cr 0.019 and Cl 0.086

3) you want to try to get all intergers in the empirical formula. so, divide both subscripts by the smallest # 0.019

4) Cr is 1 but Cl 4.526 is still not an interger. so you now multiply both numbers by the smallest multiple to convert it all to integers:

Cr (1*2) and Cl (4.5*2)

5) You get Cr 2 and Cl 9 as the empirical formula.

2007-05-02 17:29:52 · answer #1 · answered by butterfli8134 3 · 0 0

Steps for Determining an Empirical Formula
Start with the number of grams of each element, given in the problem.
If percentages are given, assume that the total mass is 100 grams so that
the mass of each element = the percent given.
Convert the mass of each element to moles using the molar mass from the periodic table.
Divide each mole value by the smallest number of moles calculated.
Round to the nearest whole number. This is the mole ratio of the elements and is
represented by subscripts in the empirical formula.
If the number is too far to round (x.1 ~ x.9), then multiply each solution by the same
factor to get the lowest whole number multiple.
e.g. If one solution is 1.5, then multiply each solution in the problem by 2 to get 3.
e.g. If one solution is 1.25, then multiply each solution in the problem by 4 to get 5

2007-05-02 17:03:29 · answer #2 · answered by brown 3 · 0 0

Figure out the g-atom weight of chromium and chlorine. Divide 1 g by the g-atomic weight of chromium. Divide the 2.045 g by the g-atomic weight of chlorine. The g-atoms you get should be in a ratio of simple integers for chromium and chlorine

2007-05-02 17:01:40 · answer #3 · answered by cattbarf 7 · 0 0

Catalyst position molecules...........=true e.g. enzymes. Enzymes at their required temperature and Ph level forms necessary shape needed to digest a substance in the stomach. Examples of enzymes are: Pepsin, amylase, e.t.c Answer: the rate decreases. Reasons: At a high temperature, a reaction is more catalysed. According to Charles' Law and Gay-Lussac's Law, "When the number of particles are constant, the volume and pressure of an ideal behaving gas is directly proportional to its temperature." Therefore, dropping the pressure of the system to 0.5 atm will affect the reaction rate through its temperature.

2016-05-19 03:49:13 · answer #4 · answered by ? 3 · 0 0

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