what's the derivative of e^-x?
2007-05-02 16:47:35 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-e^-x
2007-05-02 16:50:21 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
This is one of those things its easier to remember
the derivative of e^ of something is the derivative of that something times your original equation
e^-x = (deriv of -x )* e^-x.
derivative of -x = -1
-e^-x
pretend its
e^-2x
deriv of -2x * e^-2x...
-2e^-2x
You might not have wanted the explanation, but you are going to see this a lot
2007-05-02 17:08:34 · answer #2 · answered by My name is not bruce 7 · 0⤊ 0⤋
w4e=+8*2/2m5*7789(89)+1
2007-05-02 16:52:49 · answer #3 · answered by Wattsup! 3 · 0⤊ 1⤋
d/dx (f(g(x)) = f'(g(x)) * (g'(x))
using this formula
if f(x) = e^x implies f'(x) = e^x
and g(x) = -x implies g'(x) = -1
then f(g(x)) = e^-x
and so derivative of e^-x is -(e^-x)
2007-05-02 16:50:24 · answer #4 · answered by Harish 1 · 0⤊ 0⤋
the formula is this: (e^u)'= (u') * (e^u);
now u= -x ==> u'= -1
so e^(-x) = -e(-x)
OK?
2007-05-02 16:55:42 · answer #5 · answered by Farid 1 · 1⤊ 0⤋
d/dx e^-x=-e^-x
2007-05-02 16:52:35 · answer #6 · answered by yupchagee 7 · 0⤊ 0⤋
-e^-x
2007-05-02 16:55:42 · answer #7 · answered by sajan_surti2000 1 · 0⤊ 0⤋