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The graph of y =sec x never intersects the graph of y=
A. x
B. x^2
C. csc x
D. cos x
E. sin x

2007-05-02 15:13:35 · 5 answers · asked by Anish R. 1 in Science & Mathematics Mathematics

5 answers

well I think you can eliminate a & b right away.
then that leaves with the the trig functions

ok so sec x is 1/ cos x
well 1/cos 0 is 1
cos 0 is 1
so we know it isn't d
csc x is 1/sin x
well cos and sin intersect, so we know csc and sec will intersect at some point as well.

This leave us with e, sin x.

2007-05-02 15:21:12 · answer #1 · answered by l0uislegr0s 3 · 0 0

E:
sec x = 1/cos x
sec x touches cos x every multiple of pi. sin x never touches it.

2007-05-02 22:19:20 · answer #2 · answered by blueice 2 · 0 0

(E) y = sin(x) does not touch the y = sec(x) graph

Go to the function grapher site and look and see for yourself!

2007-05-02 22:17:35 · answer #3 · answered by Orinoco 7 · 0 0

A

2007-05-02 22:17:05 · answer #4 · answered by Rooster 1 · 0 1

B

2007-05-02 22:16:09 · answer #5 · answered by Brendon R 1 · 0 1

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