i don't understand how to do these problems.
2007-05-02 15:07:05 · 3 answers · asked by Nikki L 1 in Science & Mathematics ➔ Chemistry
grams ZnCl2 = grams zinc * (n ZnCl2/ n Zn)* (MW ZnCl2/ MW Zn)
2007-05-03 13:57:17 · answer #1 · answered by zanekevin13 4 · 0⤊ 0⤋
Use the ratio of mass of Zn to the mass of ZnCl2
Divide 36.8 g by the percentage of Zn in ZnCl2 and you have your answer
2007-05-02 22:12:38 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋
If you're balanced eq is Zn + 2Cl ---> ZnCl2,
Step 1: You do 36.8g divided by the the molecular weight of Zn (which is 65.3g)
Step 2: Then, with that answer, since the mole to mole ratio of Zn to ZnCl2 is 1:1 (as in there are no numbers in front of thos in the balanced eq), you simply divde the answer you get from Step 1 by the molecular weight of ZnCl2 (which is 136.2g)...This is your answer. :)
2007-05-02 22:21:11 · answer #3 · answered by rosesandrainydays 2 · 0⤊ 0⤋