Can someone help with these problems? Trying to earn extra credit points for a class in which I'm stuggling?

Question

1. What are the coordinates of the vertex?
y = x(squared) + 6x + 8

2. Factor 2(x squared) + 6x - 20

3. Factor 5(x squared) - 20

4. Find the value of c that makes the trinomial a perfect square. x(squared) + 5x + c

Answer 1

y= x(squared) + 6x + 8
You need to find the min point
dy/dx = 2x + 6 = 0
Then x = -3
Now put x = -3 into the equation
y = 9 -18 + 8 = -1
Vertex(-3, -1)


2. Factor 2(x squared) + 6x - 20
2(x^2 + 3x -10)
= 2(x +5)(x-2)

3. Factor 5(x squared) - 20
= 5(x^2 - 4)
= 5(x+2)(x-2)

4. Find the value of c that makes the trinomial a perfect square. x(squared) + 5x + c
(x + 2.5)^2 + c - 25/4 = 0
Perfect when c -25/4 = 0
Then c = 25/4

Answer 2

1) Y=(x+3)^2-1 V(-3,-1)

2(x^2+3x-10)
x^2+3x-10=0 so x= ((-3+-sqrt(9+40))/2
x= 2and x= -5
so=2(x-2)(x+5)
4)25-4c=0 so c= 25/4 and the trinomial is ((x+5/2)^2
3)5(x-2)(x+2)

Answer 3

first Q: (3, -1)

second Q: 2(x-5)(x+2)

third Q: 5(x+2)(x-2)

fourth Q: 6.25=c