200g of a metal at 140 degrees is dumped inot h20 and liberates 4.5x10 to 4th calories.?

Question

If the specific heat of the metal is .7 cal/g degree celcius what is the final temp

Answer 1

45000/(200*0.7) = 321°C, which is clearly an impossible ∆T with water involved, so some of the energy has to have gone into boiling some water. The final temperature must be 100°C.