2007-05-02 14:36:15 · 8 answers · asked by XOSunnyXO 1 in Science & Mathematics ➔ Mathematics
611
2007-05-02 14:39:46 · answer #1 · answered by richardwptljc 6 · 0⤊ 1⤋
13 x 47 = 611
2007-05-02 14:40:36 · answer #2 · answered by NSnoekums 4 · 0⤊ 0⤋
600/13 = 46.15 (approx)
Smallest number over 600 divisible by 13 = 13*47= 611
2007-05-02 14:38:52 · answer #3 · answered by gudspeling 7 · 1⤊ 0⤋
598/13 = 46
So 600 leaves a remainder of 2 when divided by 13.
So to get to a remainder of 0, we have to add
11 to each side of this relationship.
(Think of a clock with 13 numbers on it.)
Thus the answer is 611 = 47*13.
2007-05-02 14:42:56 · answer #4 · answered by steiner1745 7 · 1⤊ 0⤋
611
2007-05-02 14:49:43 · answer #5 · answered by Mr. Smith 5 · 0⤊ 0⤋
You need to find a number slightly bigger than 600 that when divided by 13 will yield NO remainder.
611 divided by 13 = 47
Final answer: 611
Guido
2007-05-02 14:45:09 · answer #6 · answered by Anonymous · 0⤊ 0⤋
611
2007-05-02 14:44:36 · answer #7 · answered by Mr Wizard 2 · 0⤊ 0⤋
there is dissimilar solutions to this question. for instance, in case you divide 12 into the completed volume of end result (a volume higher than 10 yet decrease than 20) than you've 882,000 baskets. 14 end result per basket equals 756,000 baskets. 15 end result per basket equals 705,600 baskets 16 end result per basket equals 661,500 baskets 18 end result per basket equals 588,000 baskets
2016-12-05 06:31:02 · answer #8 · answered by ? 4 · 0⤊ 0⤋