Kelly rode her bike 3km less than twice the number of km John rode. They rode 48km together. How far did they each ride?
2007-05-02 13:56:08 · 5 answers · asked by shiny 1 in Science & Mathematics ➔ Mathematics
K = 2J - 3
K + J = 48
2J - 3 + J = 48
3J - 3 = 48
3J = 51
J = 17
K = 2 * 17 - 3
K = 34 - 3
K = 31
2007-05-02 14:00:15 · answer #1 · answered by TychaBrahe 7 · 0⤊ 0⤋
Assume John rode x kilometers. Then Kelly rode 2x - 3. Add them together in an equation: x + 2x - 3 = 48. Solve for x and you'll have John's distance. Multiply that by two, subtract three, and you'll have Kelly's distance.
2007-05-02 21:00:52 · answer #2 · answered by Carolyn D 5 · 0⤊ 0⤋
K = 2J - 3 ---> eqn 1
K + J = 48 ----> eqn 2
subst k from eqn 1 to eqn 2
(2J - 3) + J = 48
3J = 51
J = 51/3 = 17km
K = 2*51/3 - 3 = 31 km
2007-05-02 21:01:53 · answer #3 · answered by michael_scoffield 3 · 0⤊ 0⤋
Each rode 16 km! right?
2007-05-02 20:59:25 · answer #4 · answered by WhyHello 2 · 0⤊ 1⤋
x = John
2x - 3 + (x) = 48
3x - 3 = 48
3x = 51
x = 17 = John
Kelly = 2x - 3 = 31
2007-05-02 21:01:07 · answer #5 · answered by richardwptljc 6 · 0⤊ 0⤋