factor 4w^2-15w-4 please also factor 3w^2-7?

Answer 1

4w^2-15w-4 = (4w+1)(w-4)

3w^2-7 cannot be factored over integers. However, we can use radicals with the idea that (a+b)(a-b) = a^2-b^2.

If a^2 = 3w^2, then a = √(3w^2) = w√3
If b^2 = 7, then b = √7. Thus:

3w^2-7 = (w√3+√7)(w√3-√7)

Answer 2

4w^2-15w-4
(4w+1)(w-4)

3w^2-7
(w√3 +√7)(w√3 -√7)

Answer 3

(4w + 1)(w - 4)

(sqrt(3)w - sqrt(7))(sqrt(3)w + sqrt(7))