How do you solve the equation b^2+20b+36=0?

0 ⤊

How do you solve the equation b^2+20b+36=0?

please show all steps.
Thank you very much.

2007-05-02 13:17:16 · 3 answers · asked by GO Ravens 52 2 in Education & Reference ➔ Homework Help

3 answers

b^2 + 20b+ 36 = 0
What are the factors of 36?
1, 36
2, 18
3, 12
4, 9
6, 6

Since the equation has all +, the factor must be added, so only possible solution is 2 and 18

so b = -2 or b = -18

check answer

-2^2 + 20 (-2) + 36 = 0
4 + -40 + 36 = 0

-18^2 + 20 (-18) + 36 = 0
324 + -360 + 36 = 0

2007-05-02 14:50:37 · answer #1 · answered by ohiohillbilly 4 · 0⤊ 0⤋

b = -2

b squared (b^2) = 4 (-2 * -2 = +4)

20 * b = -40 (20 * -2 = -40)

-40 + 4 = -36 + 36 = 0

2007-05-02 20:28:38 · answer #2 · answered by Erik 2 · 0⤊ 0⤋

(b+2)(b+18)=0
b+2=0
b+18=0
b=-2 or b=-18

2007-05-02 20:23:57 · answer #3 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋