need someone to check 2 sqroot problems for me?

Question

Find the cube root:

^3√125 = 5?

and....

Use the product rule to simplify the radical

√18 = 2√9?

Answer 1

For the first one, if you have a scientific calculator, you can simply insert 125^(1/3) and yes it is 5.

For the second one is incorrect.

2√9 = 6

√18 = √(2*9)

So, basically you can simplify it as √2 * √9

Knowing that √9 = 3

so it becomes 3√2

Answer 2

First one's right.

Second one is √18 = √2 * √9 = √2 * 3 = 3√2

Answer 3

first is correct
5*5*5=125

second one should be
√18=3√2
you can take out an 9 for √18, once you do, the 9 turns into a 3 (square root it), then you are left with 2 (2*9=18)
good luck!

Answer 4

The first one looks right however the second one becomes

√18 = √( 3 * 3 * 2) = 3√2
You were close.

Answer 5

1. yes 5 * 5 * 5 = 125 = 5^3 = 3root of 125
2. sqrt 18 = sqrt (9*2) = 3sqrt2
So your second answer is incorrect; you should facto 18 as 9 * 2.

Answer 6

cube root(125)=cuberoot(5^3)=5
√18 = =sqrt(2*3^2)3*sqrt(2 answer).

Answer 7

the first one, ..=5 is correct. the second is incorrect. the answer is 3\/2. V means radical sign

Answer 8

First one is correct, second one is 3√2

Answer 9

In all cases, just square the two sides to get started...for ex, sqroot(n-3)=1, squaring both sides means you lose the sqroot, since (√(x))² is just x. That is, the sqrt of x, squared, is x. On the right (in example one), 1² is 1.

Answer 10

Why you are not asking Einstein?