41 1/2 foot = 498 inches. ( 41 x 12 = 492 inches. 1/2 ft = 6 inches. 492 + 6 = 498 inches.)
3 3/4 feet = 45 inches. (3 x 12 = 36 inches. 3/4 ft = 9 inches (12 /4 = 3 x 3 = 9) 36 + 9 = 45)
498 / 45 = 11.06666
So you will have 11 equal lengths of rope + 1 very small piece.
So total equal lengths = 11
Total pieces = 12.
2007-05-02 12:47:13
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answer #1
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answered by kel 5
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Two ways to do this.
One is to subtract 3 3/4 from 41 1/2 until you run out of string... and count the number of times you subtracted
The other way is this way.
41 1/2 = 83/2
3 3/4 = 15/4
The reciprocal of 15/4 = 4/15
Multiply 83/2 by 4/15...
83/2 x 4/15 = 166/15 = 11 1/15
That means you have 11 pieces of string 3 3/4 feet long, and one little piece 3 inches long.
2007-05-02 13:02:52
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answer #2
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answered by gugliamo00 7
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41 ½ft = (41*12) + 6 ins.
41 ½ft = 492 + 6 ins.
41 ½ft = 498 ins.
3 3/4ft =(3*12) + 9 ins.
3 3/4ft = 36 + 9 ins.
3 3/4ft = 45 ins.
Total number of lengths = 498/ 45
Total number of lengths = 11∙06666........
Total number of lengths = 11 and a little bit over.
2007-05-02 12:48:30
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answer #3
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answered by Sparks 6
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83/2=41 1/2 3 3/4=15/4
166/4 into 15/4
166/15= 11 1/16 or 11 pieces
2007-05-02 13:00:05
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answer #4
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answered by Dave aka Spider Monkey 7
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about 11 pieces
2007-05-02 12:37:03
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answer #5
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answered by vg63@sbcglobal.net 1
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twelve
eleven equal lengths of 3 3/4" each
one short length of 2.7"
convert the feet to inches, then cut into lengths.
11.06 = ((41.5*12) / (3.75 * 12))
11.06 = 498 / 45
45 * .06 = 2.7
2007-05-02 12:48:24
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answer #6
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answered by bryan 1
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Why don't you ask Evette when she's done? O,K, get the calculator and divide 41.5 by 3.75 Then take the decimal remainder and multiply it by 12(inches) There's your answer
2016-05-19 01:55:58
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answer #7
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answered by Anonymous
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11 with a bit left over
11.06666667 to be ridiculous
2007-05-02 12:42:02
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answer #8
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answered by Anonymous
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11 with one little bit so maybe 12 if you want to be tricky...
2007-05-02 12:40:14
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answer #9
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answered by Anonymous
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stop asking help from your homework
2007-05-02 12:36:26
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answer #10
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answered by LASLO D 1
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