How long must a 2.00 ampere current flow to liberate 3.00 liters of oxygen measured at 27degrees celcius and 2.00 atmospheres of pressure from a solution of dilute sulfuric acid.
Answer is Seconds
2007-05-02 11:05:58 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Assuming reaction is
O(2-) -> O2 + 2e-
moles = (2*3)/(0.821*300) = 0.0244
Charge required = 0.0244*96500*2 = 4709.2 C
Thus time = 4709.2/2 = 2354.6 seconds.
2007-05-02 20:54:51 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
electron bypass is present day,and present day is amps so a million.00 x10^18th ability.present day is allways maximum on inital operation,because of initail top load.the present is ninety* to a resistive load,and ninety* is the top,the consistent voltage,and present day relies on the (RMS) root mean sq.,or hassle-free as nominal,or aka everyday variety.
2016-12-28 08:01:05 · answer #2 · answered by dunton 3 · 0⤊ 0⤋