2007-05-02 09:34:03 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
5 is the only shared constant, a^1 is the highest degree of "a" shared by all terms, b^1 is the highest degree of "b" shared by all terms, and the first term is lacking "c" so it is not a common factor:
5ab (a + 2bc - 20c^2 )
You can go a little further, though I'm not sure this is wanted. The second and third terms share factors of 2 and c:
5ab ( a + 2c ( b - 10c ) )
2007-05-02 09:39:40 · answer #1 · answered by McFate 7 · 2⤊ 0⤋
5a^2b+10ab^2c-100abc^2
Factor out 5ab:
5ab(a+2bc-20c^2)
2007-05-02 17:10:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5ab(a+2bc-20c^2)
2007-05-02 16:53:32 · answer #3 · answered by ¼½π¥¿óúñÑ⌐¿ºª 2 · 1⤊ 0⤋
5a^2b+10ab^2c-100abc^2
=5ab(a+2bc-20c^2)
2007-05-02 16:39:21 · answer #4 · answered by Anonymous · 1⤊ 1⤋
ohh snap i totally suck @ this....
5ab(2+4c+40c)....idk.....lol
2007-05-02 16:43:10 · answer #5 · answered by <3 2 · 0⤊ 1⤋