How exactly is this gonna work? Too many stars on one team DOES NOT work. No matter who the players are, Peyton Manning will destroy them.
2007-05-02 09:26:48 · 7 answers · asked by Anonymous in Sports ➔ Football (American)
And the TRADED for randy moss, lol unreal, who want want him or T.O on a team?
2007-05-02 09:28:06 · update #1
Pats are gonna suck!!
2007-05-02 12:34:26 · answer #1 · answered by Anonymous · 2⤊ 1⤋
Come on, let's have some grip on reality here. Peyton has never been able to destroy the Patriots. I he has only beaten them once or twice in his entire career (last AFC Championship), and he didn't exactly destroy them then.
Face it, the Patriots are the team to beat next season.
Patriots > Chargers > Colts
2007-05-02 17:07:13 · answer #2 · answered by Anonymous · 0⤊ 2⤋
They are trying to stay ahead of the Jets. I agree Randy Moss is a BIG mistake! Who is next, Keyshawn Johnson is now available.
2007-05-02 20:34:16 · answer #3 · answered by Bawney 6 · 1⤊ 1⤋
The Patriots just LET you borrow the Lombardi Trophy last season so Peyton would stop whining...The DYNASTY that is THE PATRIOTS will resume next season...Does the movie "Rambo" ring a bell?..."Colts...We're coming to get YOU!!!..."
2007-05-02 16:51:38 · answer #4 · answered by Terry C. 7 · 0⤊ 2⤋
ha! ha! tis to laugh!! the colts just lost several key players whilke the patriots got stronger! guess what, dummy? your colts!!1 are toast this coming year! no repeat! in fact, the bengals w ill be beter than the colts!! ha! ha! peyton manning will get sacked 45 times rthis year, and get injured!
2007-05-02 16:41:39 · answer #5 · answered by Anonymous · 1⤊ 2⤋
They have just reloaded their gatlin gun. They have just made renovations to the Dynasty. They are going to destroy the Colts!
2007-05-02 16:32:08 · answer #6 · answered by J Dub 5 · 2⤊ 2⤋
Stop crying, you got your super bowl victory thanks to the Pats disinterest last season.. Now its time for the Pats to take back what is rightfully theirs.
2007-05-02 16:48:46 · answer #7 · answered by Ballzy 6 · 0⤊ 2⤋