can someone please help me/answer with these math problems?

Question

1. 6z+3=8z-5
2. 3-4z=-5+8z
3. 5x+14-2x=9-(4x+2)
4. (5/2)-x(x+1)=x(2-x)
5. 7z+5=9z-3

Answer 1

You need to do your own homework.

Answer 2

the whole thing is PROCESS!, isolate the variable to one side, then put everything else on the other!, Reduce as you need to. any identical item on the same side, with oposite signs, is zero(example: -(x^2) +(x^2) =0, where ^ is to the power of. so terms like that can be crossed out.) Process makes this easy, learn the process, and this will be nothing to you


1.
6z+3=8z-5
6z-6z+3=8z-6z-5
3=2z-5
3+5=2z-5+5
8=2z
8/2=2z/2
4=z
CHECK
6(4)+3=8(4)-5
24+3=32-5
27=27---->TRUE
2.
3-4z=-5+8z
3-4z+4z=-5+8z+4z
3=-5+12z
3+5=-5+5+12z
8=12z
8/12=12z/12
2/3=z
CHECK
3-4(2/3)=-5+8(2/3)
3-2_2/3=-5+5_1/3
1/3=1/3------------>TRUE
3.
5x+14-2x=9-(4x+2)
3x+14=9-4x-2
3x+4x+14=9-4x+4x-2
7x+14=7
7x+14-14=7-14
7x=-7
7x/7=-7/7
x=-1
CHECK
5(-1)+14-2(-1)=9-(4(-1)+2)
-5+14+2=9-(-4+2)
11=9+4-2
11=11------------>TRUE
4.
(5/2)-x(x+1)=x(2-x)
(5/2)-x(x+1)+x(x+1)=x(2-x)+x(x+1)
5/2=x(2-x)+x(x+1)
5/2=2x-x^2+x^2+1x
5/2=2x+1x
5/2=3x
(5/2)/3=3x/3
5/6=x
CHECK
(5/2)-(5/6)((5/6)+1)=(5/6)(2-(5/6))
(5/2)-(5/6)(11/6)=(5/6)(7/6)
(5/2)-(55/36)=(35/36)
(90/36)-(55/36)=(35/36)
(35/36)=(35/36)-------------->TRUE
5.
7z+5=9z-3
7z-7z+5=9z-7z-3
5=2z-3
5+3=2z-3+3
8=2z
8/2=2z/2
4=z
CHECK
7(4)+5=9(4)-3
28+5=36-3
33=33----------->TRUE

I have fun with these, but if nobody else does your homework for you, then I expect best answer! ;-)

Answer 3

what you need to do is combine like terms first. like on the first one, 6z+3=8z-5, move 6z to the other side (3=2z-5) then move -5z to the other side, which gives you 8=2z, then divide by 2, giving you the answer of 4=z

Answer 4

1. 6z+3=8z-5
=>+3+5=8z-6z
=>8=2z
i.e. z=4

what you need is math tutor.
but not me, me only good in math no teaching

Answer 5

1.z=4
2.z=3/4
3.you do the rest