Solve Algebraically and show work please...
(the fourth root of t plus 8)=(the fourth root of 2t)
2007-05-02 09:08:52 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Since both sides of the equation are "fourth root of", the stuff under the radical on each side are equal.
t + 8 = 2t
8 = t
2007-05-02 09:16:06 · answer #1 · answered by Mathematica 7 · 1⤊ 0⤋
to get rid of the fourth root multiply by the fourth power and you will end up with T + 8 = 2T subtract T from both sides for the equation and you will end up with T = 8
2007-05-02 16:14:54 · answer #2 · answered by justplainme64 3 · 1⤊ 0⤋
Is the 8 underneath the radical? If so,
since they're both the 4th root, take both sides to the fourth power to get rid of the radicals . That leaves you with :
t+8 = 2t
t= 8
2007-05-02 16:16:05 · answer #3 · answered by Baysoc23 5 · 1⤊ 0⤋
(the fourth root of t plus 8)^4=(the fourth root of 2t)^4
t + 8 = 2t
8 = t
2007-05-02 16:15:58 · answer #4 · answered by Anonymous · 1⤊ 0⤋
raise each side of the equation to the power of four. this will cancel the fourth roots out so you have:
t + 8=2t
subtract t from both sides
8=t ot t=8
2007-05-02 16:17:46 · answer #5 · answered by Anonymous · 1⤊ 0⤋
yeah, raise both sides to the 4th power to get rid of the fourth roots so you're left with:
t+8=2t
subtract t on both sides:
t=8
2007-05-02 16:15:20 · answer #6 · answered by Anonymous · 1⤊ 0⤋
(t+8)^1/4= (2t)^1/4 tmust be >=0
raising to the fourth power
t+8=2t so t=8
2007-05-02 16:14:48 · answer #7 · answered by santmann2002 7 · 1⤊ 0⤋
4^ât+8=4^â2t
Take both sides to the power of 4:
(4^ât+8)^4=(4^â2t)^4
t+8=2t
-t+8=0
-t=-8
t=8
Check:
4^â8+8=4^â2(8)
4^â16=4^â16
2=2
2007-05-02 17:25:30 · answer #8 · answered by Anonymous · 0⤊ 0⤋
raise both sides to the 4th power to get rid of the fourth roots then you are left with
t+8=2t
subtract from both sides and........
t=8
2007-05-02 16:18:58 · answer #9 · answered by dancerrox1201 2 · 1⤊ 0⤋