Math question?

1 ⤊

Using the Pythagorean Identities,

What is sec²x + csc²x

²=to the 2nd power

Your choices are:

A. 1
B. 1/sinxcosx
C. (sec x)(csc x)
d. 1/sin²xcos²x

thanks!

2007-05-02 09:03:31 · 2 answers · asked by staci3925 s 1 in Science & Mathematics ➔ Mathematics

2 answers

d.

since secx = 1/cosx, cscx = 1/sinx,

sec²x + csc²x =
1/cos²x + 1/sin²x =
(cos²x + sin²x) / cos²x sin²x =
1 / cos²x sin²x

2007-05-02 09:08:20 · answer #1 · answered by iluxa 5 · 1⤊ 0⤋

sec x = 1/cos x
csc x = 1/sin x

sec^2(x) + csc^2(x) = 1/cos(x)^2 + 1/sin(x)^2 = [sin(x)^2 +
+ cos(x)^2]/[sin(x)^2 * cos(x)^2] = 1/[sin(x)^2 * cos(x)^2]

The answer is d.

2007-05-02 16:11:13 · answer #2 · answered by Amit Y 5 · 0⤊ 0⤋