maths help - lines/gradients/points on a line?

Question

the question that i am stuck on says;

the point (3k,k) lies on line AB
find the value of k

the line AB has the following co-ordinates
A(-1, -7) B(4,3) and it cuts the y axis at (0, -5)

the line equation therefore is y= 0.5x - 5

so how do i find a point on that line? the k? any help much appreciated

sorry the equation is not o.5x-5

it is actually y=2x-5

Answer 1

Plug in the (3k, k) for x and y in the equation and solve.

y = (0.5)x - 5
k = (0.5)(3k) - 5
k = 1.5 k - 5
-0.5 k = -5
k = 10

So, the point is (30, 10)

Answer 2

The equation is
y+7 =2(x+1)
y= 2x-5
Now give x and y the givwn values
k=6k-5
-5k=-5 k=1

Answer 3

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Answer 4

All you do is replace x with 3k and y with k. So:
k= 0.5 (3k) -5
k= 1.5k -5
Then put the k's on one side by subtracting 1.5 both sides:
-0.5k= -5
Then divide both sides by (-0.5), so
k=10.

Answer 5

I believe the slope is really 2, not 0.5