This is the problem that I got on my homework:
Acetylcholine esterase, 3.0 mg, was dissolved in 10.0 mL solution. From this solution, 0.60 mL was added to the sample tube, bringing the volume to a total of 3.0 mL. How many mg of acetylcholine esterase did you have in the sample tube?
2007-05-02 08:20:01 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Has nothing to do with moles. It is just a percentage calculation
If 3.0 mg was dissolved in a 10.0 ml solution. Now you withdrew 0.60 ml of that solution. So you withdrew 6% of the original quantity.
So calculate 6% of your starting 3.0 mg and you have the answer
2007-05-02 08:32:00 · answer #1 · answered by reb1240 7 · 0⤊ 1⤋
hmm... an aliquot...
3.0 mg *(0.60 mL / 10.0 mL) = mg acetylcholine esterase
2007-05-03 03:37:22 · answer #2 · answered by zanekevin13 4 · 0⤊ 1⤋
Hint: Try converting to moles first.
2007-05-02 15:27:09 · answer #3 · answered by Joe 4 · 0⤊ 1⤋