2007-05-02 08:11:43 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
27=3^3
2x-1=3
2x=4
x=2
2007-05-02 08:15:37 · answer #1 · answered by iyiogrenci 6 · 0⤊ 1⤋
If you mean 3^(2x-1) = 27, then take the log of both sides. This lets you move the exponent down (using the rule that log(x^a) = a log (x)). Another way to do it is to know that 27 = 3^3, meaning 2x - 1 = 3.
If you mean (3^(2x)) - 1 = 27, then add 1 to both sides, and then add the log.
2007-05-02 10:17:06 · answer #2 · answered by ¼½π¥¿óúñÑ⌐¿ºª 2 · 0⤊ 0⤋
If you mean 3^(2x-1) = 27, then take the log of both sides. This lets you move the exponent down (using the rule that log(x^a) = a log (x)), making it much easier to solve for x. Another way to do it is to realize that 27 = 3^3, so this means 2x - 1 = 3.
If you mean (3^(2x)) - 1 = 27, then add 1 to both sides, and THEN apply the log.
2007-05-02 08:14:49 · answer #3 · answered by Anonymous · 0⤊ 1⤋
the answer is 2. (2X2)-1= 3
3^3=27
2007-05-02 08:15:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i wont tell you how to do it,
i'll just say "logs"
2007-05-02 08:14:52 · answer #5 · answered by jjtfff 2 · 0⤊ 0⤋