E for cell reaction is -0.89?
2007-05-02 06:08:28 · 4 answers · asked by dasdaner 1 in Science & Mathematics ➔ Chemistry
The overall ionic equation is
3Sn(4+) + 2Cr ----------> 2Cr (3+) + 3Sn(2+)
2Cr ----------> 2Cr(3+) + 6e (equation 1) E= 0.74*2 = 1.48V
3Sn(4+) + 6e ----------> 3Sn(2+) (equation 2) E= 0.15*3 = 0.45V
add equations 1and 2
E= 1.48 +0.45 = 1.93V
2007-05-02 06:18:35 · answer #1 · answered by The exclamation mark 6 · 0⤊ 1⤋
Balance the equations first. Then Ecell=Ecathode-Eanode
2007-05-02 06:12:38 · answer #2 · answered by Chris 5 · 0⤊ 1⤋
You never, ever multiply electrode potentials by balancing numbers. I can't believe that a "Top Contributor" has suggested it.
The overall voltage is E(right) - E(left) = 0.15 - (-0.74) = +0.89V.
2007-05-02 06:32:18 · answer #3 · answered by Gervald F 7 · 0⤊ 2⤋
Ecell = E.r.hs. -E.l.h.s
=0.15-(-0.74)
=0.89V
2007-05-02 07:14:19 · answer #4 · answered by chaveen 2 · 0⤊ 1⤋