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thanks for answering !!!!!!!!!!!!!

2007-05-02 05:59:03 · 2 answers · asked by edbiology 1 in Science & Mathematics Physics

2 answers

There are two paths from the (light) source to the detector. One reflects off the semi-transparent mirror, goes to the top mirror and then reflects back, goes through the semi-transparent mirror, to the detector. The other first goes through the semi-transparent mirror, to the mirror on the right, reflects back to the semi-transparent mirror, then reflects from the semi-transparent mirror into the detector.

If these two paths differ by a whole number (including 0) of wavelengths, there is constructive interference and a strong signal at the detector. If they differ by a whole number and a half wavelengths (e.g., 0.5, 1.5, 2.5 ...) there is destructive interference and a weak signal. This might appear at first sight to violate conservation of energy. However energy is conserved, because there is a re-distribution of energy at the detector in which the energy at the destructive sites are re-distributed to the constructive sites. The effect of the interference is to alter the share of the reflected light which heads for the detector and the remainder which heads back in the direction of the source.

2007-05-02 06:01:12 · answer #1 · answered by DanE 7 · 0 0

Try here ...

http://en.wikipedia.org/wiki/Michelson_interferometer

2007-05-02 06:02:22 · answer #2 · answered by Gene 7 · 0 0

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