This is gonna sound confusing.
On a circle with centre (0,0), is the equation of the right bisector of the chord always y=mx?
2007-05-02 05:29:23 · 2 answers · asked by wolfangel88 1 in Science & Mathematics ➔ Mathematics
Since the perpendicular bisector of a chord always passes through the center of the circle, and since the center is at (0,0), then your line has the origin as y-intercept and so its equation will be y = mx, except for a chord that's parallel to the x-axis.
2007-05-02 05:34:40 · answer #1 · answered by Philo 7 · 0⤊ 0⤋
Its fake The perpendicular bisector of a chord passes for the time of the centre of a circle, so all of us be attentive to the y intercept of the line is 0. yet whilst this is at precise angles to a chord with slope of m, its slope is -a million/m, so the equation of the line may well be y = -a million/m (x)
2016-12-10 17:22:31 · answer #2 · answered by ? 4 · 0⤊ 0⤋