In how many different ways can someone arrange 8 books on a shelf?
362,880
40,320
36
4,096
2007-05-02 05:21:27 · 9 answers · asked by keema w 1 in Science & Mathematics ➔ Mathematics
8! = 8*7*6*5*4*3*2*1 = 40320
2007-05-02 05:24:32 · answer #1 · answered by Mathematica 7 · 0⤊ 1⤋
The answer would be 8! or 8 factorial:
8 X 7 X 6 X 5 X 4 X 3 X 2 X1 = 40,320
2007-05-02 05:29:14 · answer #2 · answered by wxscooter 2 · 0⤊ 0⤋
40,320
8*7*6*5*4*3*2*1 = 40,320
2007-05-02 05:25:00 · answer #3 · answered by Kathryn 6 · 0⤊ 0⤋
OK, the first position can have any of eight books; the second any of the remaining seven; and so on. So the answer is 8! (eight factorial) which is 40,320.
2007-05-02 05:25:49 · answer #4 · answered by Mark S, JPAA 7 · 0⤊ 0⤋
the answer is 8! which broken down would be 8*7*6*5*4*3*2*1 so the answer is 40,320.
and thanks for the multiple choice! :)
2007-05-02 05:31:34 · answer #5 · answered by dont care what it is! 2 · 0⤊ 0⤋
8! = 40,320
2007-05-02 05:25:26 · answer #6 · answered by Philo 7 · 0⤊ 0⤋
In this case, arrangement is important, so you use 8! which gives you 40320
2007-05-02 05:29:01 · answer #7 · answered by the DoEr 3 · 0⤊ 0⤋
40320
2007-05-02 05:24:56 · answer #8 · answered by JDC 2 · 0⤊ 0⤋
40320
2007-05-02 05:24:48 · answer #9 · answered by kitten 2 · 0⤊ 0⤋