A hockey team has red sweaters, white sweaters and blue sweaters. The team uses red or blue pants and red or white socks. Find the number of possible uniforms.
12
7
5
10
2007-05-02 05:20:54 · 6 answers · asked by keema w 1 in Science & Mathematics ➔ Mathematics
No of ways of picking a sweater = 3C1 = 3
No of ways of picking pants = 2C1 = 2
No of ways of picking socks = 2C1 =2
As these can go with anyone ,total number of combination=
3*2*2 = 12
2007-05-02 05:34:30 · answer #1 · answered by The Indoian 2 · 0⤊ 0⤋
3 sweaters * 2 pants * 2 socks = 12
2007-05-02 05:24:08 · answer #2 · answered by Kathryn 6 · 0⤊ 0⤋
12
2007-05-02 05:23:52 · answer #3 · answered by kitten 2 · 1⤊ 0⤋
3*2*2=12
2007-05-02 05:29:06 · answer #4 · answered by Megs 3 · 0⤊ 0⤋
3 choices for sweater x 2 choices for pants x 2 choices for socks = 12 choices.
2007-05-02 05:24:23 · answer #5 · answered by Philo 7 · 0⤊ 0⤋
Well, three colors of sweaters times two colors of pants times two colors of socks (3x2x2) = 12.
2007-05-02 05:24:27 · answer #6 · answered by Mark S, JPAA 7 · 0⤊ 0⤋