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If the conserved constants of the physical universe sum to precisely zero, does this means that everything that seems to exist is a symmetrical deviation from nothingness, and therefore nothing exists?

2007-05-02 04:56:23 · 4 answers · asked by ThinkaboutThis 6 in Science & Mathematics Physics

4 answers

Since most all physical constants are positive and have different dimensions they couldn't sum to zero. It would be better to ask if there is an equation relating all fundamental dimensionless constants. This would not be a simple add/subtract equation. According to the standard model there is no such equation, but then again the standard model isn't necessarily correct - it's just a theory. The closest thing to what you are asking for is given by Planck mass, Planck length, and Planck time.
Any equation can be made equal to zero if everything is put on the left hand side. For example x^2 - 4x = 25 is the same as x^2 - 4x - 25 = 0. Even for very complex equations this can be done, so the point of finding some equation of the dimensionless constants that equals zero is mute. If there is any equation at all relating the constants you can always rearrange things to make them equal to zero, but this is true of any equation (except in some abstract algebra's where there is no zero).

2007-05-02 06:37:25 · answer #1 · answered by Anonymous · 0 0

You are right in that they should. However, their sum is very close to zero, but slightly, very slightly, larger. This is in fact because the universe is assymetrical, a fall from perfect symmetry. Some say that assymetry is why we are here today!

2007-05-02 18:03:42 · answer #2 · answered by Evil Genius 3 · 0 0

No. That very imprecision is what resulted in the known universe. The Big Bang ALMOST completely cancelled itself out. We are what was left over.

2007-05-02 12:06:33 · answer #3 · answered by Michelle C 4 · 0 0

What conserved constants might you be talking about? Most conserved constants you might think of are not Lorentz invariant in any case, so the anwer to your question is probably:

NO

2007-05-02 12:00:24 · answer #4 · answered by Anonymous · 0 1

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