2007-05-02 03:47:01 · 2 answers · asked by jiao 1 in Science & Mathematics ➔ Chemistry
By far the best answer is the ionic equation:
Ce4+ + 2Fe2+ -----> Ce2+ + 2Fe3+
2007-05-02 06:47:52 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
v(KMnO4)=26.32ml=0.02623L m(FeSO4(NH4)2SO4= 1.041g Molar mass(FeSO4(NH4)2SO4.6H2O=392.0g/mol moles=mass/molar mass n=2.656moles KMnO4 + FeSO4(NH4)2SO4.6H2O---> moles of KMnO4/0.02623L v=volume m=mass n=moles Molarity= concentration/volume i couldn't write the products but if the reactants have a mole ratio of 1:1 ,then 1mole of FeSO4(NH4)2SO4.6H2O =1mole of KmnO4. Therefore moles of KMnO4 =2.656moles of FeSO4(NH4)2SO4 so the molarity(concentration) which is equal to moles/volume c=n/v => c=2.656moles/0.02623L=101.2M the answer seems quite a large number.Check your question again to see if you provided the right information because i know i followed the correct procedure. Check this compound "FeSO4(NH4)2SO4.6H2O" very well.The problem might be from maybe the ".6H2O".if there's nothing wrong with your information then you've got the correct answer.
2016-05-18 22:13:43 · answer #2 · answered by ? 3 · 0⤊ 0⤋