Divide 40x/64y by 5x/8y?

320y/320x= 1y/1x

2007-05-02 03:22:12 · answer #1 · answered by limitedgirl_t 3 · 0⤊ 8⤋

This is how I would get the answer and the explanation. When dividing by a fraction, you have to multiply the top fraction by the reciprocal of the bottom fraction. So:
40x/64y * 8y/5x.

You can cross cancel the the 8y to be y and the 64y to be 8y (8 goes into 64 8 times). You can cross cancel the 5x to be x and the 40x to be 8x (5 goes into 40 8 times).

This leaves: 8x/8y * y/x = 8xy/8yx. This will cancel out and =1.

2007-05-02 03:33:41 · answer #2 · answered by Anonymous · 0⤊ 1⤋

To divide by a fraction, simply multiply by its reciprocal.

(40x / 64y) / (5x / 8y) = (40x / 64y)(8y / 5x) = (40x8y) / (64y5x) = (40*8) / (64*5) = 320 / 320 = 1

As you can see, x and y canceled out handily, leaving only numbers. If you'd like to continue canceling integer factors instead of multiplying those numbers out, take it from (40*8) / (64*5) = (8*1) / (8*1) = 1. I canceled out 5 from 40 in the numerator and 8 from 64 in the denominator.

2007-05-02 03:21:52 · answer #3 · answered by DavidK93 7 · 8⤊ 0⤋

40x/64y / 5x / 8y

To divide fractions, just multiply the first term by the reciprocal of the second term.

A/B divided by C/D =

A/B x D/C

To multiply fractions, multiply the numerator of the first term by the numerator of the second term, multiply the denominator of the first term by the denominator of the second term

A/B x D/C = (A x D)/(B x C)

Back to the problem:

40x/64y / 5x/8y =
40x/64y x 8y/5x =

(40x times 8y)/ (64y times 5x) =

320xy/320xy = 1 ===> the answer

2007-05-02 03:35:50 · answer #4 · answered by detektibgapo 5 · 6⤊ 0⤋

40x/64y ÷ 5x/8y = 40x/64y × 8y/5x = 40x × 8y / 5x × 64y

Cancelling down gives: 8 × 1 / 8 = 1

2007-05-02 03:24:54 · answer #5 · answered by peateargryfin 5 · 4⤊ 0⤋

40x/64y by 5x/8y = 40x/64y * 8y/5x = 8/8 = 1

2007-05-02 03:24:05 · answer #6 · answered by tick 2 · 4⤊ 0⤋

40x/64y divided by 5x/8y = 40x/64y x 8y/5x = 5x/8y x8y/5x = 1

2007-05-02 03:26:40 · answer #7 · answered by Kalyansri 5 · 3⤊ 0⤋

40x/64y by 5x/8y=

40x/64y x 8y/5x=
1

2007-05-02 03:47:12 · answer #8 · answered by MARY J 1 · 3⤊ 0⤋

40x/64y X 8y/5x =
8x/8y=
x/y

2007-05-02 03:28:19 · answer #9 · answered by Miss_Strawberry 1 · 1⤊ 0⤋

40x/64y / 5x/8y
40x/64y x 8y/5x
8/64y x 8y
therefore ans is 1

2007-05-02 03:27:37 · answer #10 · answered by U know who 3 · 2⤊ 0⤋

(40x/64y)
-------------------
(5x/8y)

=(40x/64y)*(8y/5x) interchange the and nume- rator and the denominator of 5x/8y then
multiply with 40x/64y

= (40x * 8y)/(64y*5x)
=(320xy)/(320xy) when we divide the same number we
get 1
=1

2007-05-02 03:35:50 · answer #11 · answered by jan-na~♥~ and im luvin it 6 · 1⤊ 0⤋

Divide 40x/64y by 5x/8y?

17 answers