2007-05-02 02:19:51 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Any number x where x=y^6 and y is an integer.
Eg.
2^6=64=8^2=4^3 ----(2^3)^2 or (2^2)^3
3^6=729=27^2=9^3 ----(3^3)^2 or (3^2)^3
x^6=(x^2)^3
x^6=(x^3)^2
2007-05-02 02:24:45 · answer #1 · answered by gudspeling 7 · 4⤊ 0⤋
Any 6th power of a natural number would work,
since a^6 = (a²)³ = (a³)².
The smallest 6th power is 64 = 8² = 4³.
The next one is 729 = 27² = 9³.
2007-05-02 02:39:17 · answer #2 · answered by steiner1745 7 · 2⤊ 0⤋
The answer is 64.
64 is the square of 8 (a perfect cube, 2*2*2) because 8*8 = 64.
64 is the cube of 4 (a perfect square 2*2) because 4*4*4 = 64.
2007-05-02 02:25:11 · answer #3 · answered by T F 4 · 0⤊ 3⤋
The sixth power of any natural number will qualify, e.g. 64.
2007-05-02 02:25:01 · answer #4 · answered by Anonymous · 3⤊ 0⤋