In optical physics, white is the combination of all colored lights, which is why, when it is decomposed, you can see them all, like in a rainbow. Black is the absence of light, and therefore, color. That is why, when there's no light, everything is black.
2007-05-02 02:00:48
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answer #1
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answered by Dr Strangelove 2
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To make black you have to mix colors.....white is the reflection of light or no color. So the absent of color is white.
2007-05-02 01:29:51
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answer #2
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answered by Barbiq 6
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Black is the absents of color and white is the presence of all colors. I know you have seen the experiment of passing white light through a prism and "rainbow" of color shines through the other side of the prism.
2007-05-02 15:39:01
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answer #3
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answered by Mr Wizard 2
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White is the absents of color..
2007-05-02 01:28:48
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answer #4
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answered by Dixie 6
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Black!
2007-05-02 02:00:04
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answer #5
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answered by rose_brit3 2
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There are actually two answers for this...
In light, white is the presence of all color and black is void of all color.
In pigments, it is just the opposite.
2007-05-02 01:27:35
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answer #6
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answered by DaysofSweetLight 4
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black is the absent color.
white is the presence of all colors in the spectrum, while black is the absense of all colors in the spectrum.
2007-05-02 01:27:30
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answer #7
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answered by engineeringguru 2
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Think about it... it depends! In terms of light, black is the absence of color and white the presence of ALL wavelengths. In terms of pigment, though, it can be the reverse...
2007-05-02 05:51:35
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answer #8
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answered by Anonymous
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in light black is the absent of all color, but in solid matter white is... i think???....
2007-05-02 01:33:28
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answer #9
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answered by chatyboy8 2
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Black is the absence/absorption of color and white is the presence/reflectance of all colors.
2007-05-02 01:23:25
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answer #10
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answered by HearKat 7
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