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A #6 is English is written #6 in chinese letter. A number 5x in English is the same in 5x in German. Knowing Maths is an international lang. simbolim so on.

Math really pisses me off.

Right now I cant even find out the difference between 3ax^2-9ax-12a=?
I know: 3a(x^2-9x-12)=
3a(x-3x-4)=
Now: 3a(x-?)(x+?)
Awww...Im so mad at math I cant even solve a single thing. i just need help of find the Common # that can be times and added to create the middle monomial!

I need help, im so frustrated with math I stayed up to 1:30am Grrrr...HELPS PLEASE TY

2007-05-01 19:23:29 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

GRRR yourself. You know you can't do the x^2-9x-12 = (x-3x-4) That's not "kosher" in another language. You didn't even factor right to start. If you pull a "3" out of the expression, you have to divide each term in that expression by 3. So the original expression factors to 3a(x^2-3x-4), which factors to 3a(x-4)(x+1). It's not the common number that is tripping you up, it's not knowing the basic rule of factoring.

2007-05-01 19:32:38 · answer #1 · answered by cattbarf 7 · 0 0

Well....... You could always practice saying, "Would you like an order of fries with that?" ☺

As for your problem, you're looking for 2 numbers whose product is -4 and whose sum is -3. How about 1 and -4? Then
3a(x-4)(x+1)
and you can go to bed and quite whining.

Math isn't all that easy or simple even for those of us who really like it. But it's like any other sport. If you want to get good at it, you have to play. You can't just set around and watch other people doing it ☺

Doug

2007-05-01 19:33:35 · answer #2 · answered by doug_donaghue 7 · 0 0

Are you trying to simplify 3a(x^2-9x-12)?

3a(x^2-9x-12)=
3a(x-3x-4)=
3a(x-4)(x+1)

2007-05-01 19:29:34 · answer #3 · answered by Venom 1 · 0 0

it is x-4 multiplied by x+1, cuz -1 * 4 is equal to -4 and -4 + 1 is equal to -3. did u get it???

2007-05-01 19:29:47 · answer #4 · answered by Anonymous · 0 0

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2016-10-04 06:04:15 · answer #5 · answered by duktig 4 · 0 0

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