Okay I know that amonnium is NH4 and carbonate is CO3. so to find the amount of ammonium ions would I take the .837 g divided by 1 mole of amonnium carbonate multiplied by 1 mole of ammonium? confused
2007-05-01 19:19:46 · 3 answers · asked by Walachka 3 in Science & Mathematics ➔ Chemistry
molecular mass of (NH4)2CO3 = 96
96 gms of (NH4)2CO3 contains 2 gm-ion NH4 + ions
=>0.837gms of (NH4)2CO3 contains 2 x 0.837/96 gm-ion NH4 + ions
=0.01744 gm-ions (or mols)
2007-05-01 19:26:16 · answer #1 · answered by s0u1 reaver 5 · 0⤊ 0⤋
You seem to be tying yourself up in knots. Find the mol weight of ammonium carbonate. Divide 0.837 g by that. This will give you the moles of ammonium carbonate. This is also equal to the moles (better g-ions) of ammonium ion in that salt.
2007-05-01 19:25:50 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
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2016-05-17 08:15:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋