solve this?

Question

x-(square root of) 9-3x=0

Answer 1

The sqn is

x-sqrt(9-3x) = 0

Thus, x^2 = 9-3x
or x^2+3x-9 = 0
So, x = (-3+sqrt(45)).2 = 3(-1+sqrt(5))/2 and 3(-1-sqrt(5))/2

Answer 2

x-√9-3x=0

Square both sides:
(x-√9-3x)^2=(0)^2
x^2-(9-3x)=0
x^2+3x-9=0

Use the quadratic formula:
x=-b±√b^2-4ac/2a
a=1,b=3,c=-9
x=(-3±√(3)^2-4(1*-9))/2(1)
x=(-3±√(3)^2-4(-9))/2
x=(-3±√9+36)/2
x=(-3±√45)/2
x=(-3±3√5)/2