Calculate the theoretical yield?

Question

A sample of 70.5 mg of potassium phosphate is added to 15.0 mL of 0.050M silver nitrate. Calculate the theoretical yield of the precipitate that formed.

Answer 1

K3PO4 + 3AgNO3 -> Ag3PO4 + 3KNO3

millimol of AgNO3 = .75

millimol of K3PO4 = 0.33

Thus moles of Ag3PO4 = (.75x10^-3)/3 = .25x10^-3

Molar mass of Ag3PO4 = 419 g

Thus mass formed = 104.75 mg