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solve the equation sin3x = -(radicle 3)/2?

2007-05-01 16:28:22 · 1 answers · asked by nicole p 1 in Science & Mathematics ➔ Mathematics

over the interval [ 0, 2pi )

2007-05-01 16:34:58 · update #1

1 answers

arcsin(-sqrt(3)/2)=320 degrees
so 3x=320 or 3x=240
so x=320/3 or x=240/3

2007-05-01 16:34:36 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋

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