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4(r - 3) = 8

explain....thanks

2007-05-01 16:22:28 · 16 answers · asked by Anonymous in Science & Mathematics Mathematics

16 answers

4(r-3)=8
4r - 12 = 8
4r = 20
r = 5

2007-05-01 16:25:43 · answer #1 · answered by Anonymous · 1 0

4(r-3) = 8 Multiply through the left side
4r - 12 = 8 Add 12 to each side
4r = 20 Divide each side by 4
r = 5 Done

HTH

Doug

2007-05-01 16:29:30 · answer #2 · answered by doug_donaghue 7 · 0 0

use the distributive property to get 4r-12 on the left. Add 12 to both sides to get 4r=20. Divide both sides by 4. The answer is r=5. Voila!

2007-05-01 16:26:31 · answer #3 · answered by mushuflare 3 · 1 0

4(r - 3) = 8 divide both sides by 4
r-3=2 add 3 to each side
r=5

2007-05-01 16:37:35 · answer #4 · answered by yupchagee 7 · 0 0

First, rewrite the equation:
4(r - 3) = 8

Then, expand your equation:
4r - 12 = 8

Next, put the unknown on the LHS and values on the RHS:
4r = 8 + 12 (you must change the +/- signs when switching sides)

Finally, solve it:
4r = 20
r = 20/4
r = 5 (final answer)

2007-05-01 16:30:26 · answer #5 · answered by dchosen1_007 2 · 2 0

4r - 12 = 8
Need to multiply with 4 using the distribution. And add 12 to both side, will get 4r=20, divide both side by 4 and r=5.

2007-05-01 16:33:45 · answer #6 · answered by K@ti3 2 · 0 0

first divide throughout by 4 so the equation now becomes
r-3 = 2
add 3 to both sides to make r the subject of the formula
so r=5

2007-05-01 16:27:09 · answer #7 · answered by khadie19 1 · 0 0

4 x (r - 3) = 8
8/4 = 2
2 + 3 = 5
r = 5

2007-05-01 16:29:44 · answer #8 · answered by Kevin H 7 · 0 0

4(r-3)=8
r-3=8/4
r-3=2
r=5


or

2^2(r-3)=2^3
so the term r-3 must be 2 to get the same powers on both sides.
r-3=2
or r=5

2007-05-01 16:30:52 · answer #9 · answered by K R 2 · 0 0

First, do the problem in the parentheses.
(r-3)
4 times what = 8
what=sum of r-3
AS you know r=5
Answer:4(5-3=2)=8

2007-05-01 16:34:33 · answer #10 · answered by betty:] 3 · 0 0

4(r - 3) = 8
(r - 3) = 8/4
r - 3 = 2
r = 3 + 2
r = 5

2007-05-01 16:27:33 · answer #11 · answered by Rhiaven 2 · 1 0

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