4(r-3)=8
4r - 12 = 8
4r = 20
r = 5
2007-05-01 16:25:43
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answer #1
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answered by Anonymous
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4(r-3) = 8 Multiply through the left side
4r - 12 = 8 Add 12 to each side
4r = 20 Divide each side by 4
r = 5 Done
HTH
Doug
2007-05-01 16:29:30
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answer #2
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answered by doug_donaghue 7
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use the distributive property to get 4r-12 on the left. Add 12 to both sides to get 4r=20. Divide both sides by 4. The answer is r=5. Voila!
2007-05-01 16:26:31
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answer #3
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answered by mushuflare 3
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4(r - 3) = 8 divide both sides by 4
r-3=2 add 3 to each side
r=5
2007-05-01 16:37:35
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answer #4
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answered by yupchagee 7
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First, rewrite the equation:
4(r - 3) = 8
Then, expand your equation:
4r - 12 = 8
Next, put the unknown on the LHS and values on the RHS:
4r = 8 + 12 (you must change the +/- signs when switching sides)
Finally, solve it:
4r = 20
r = 20/4
r = 5 (final answer)
2007-05-01 16:30:26
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answer #5
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answered by dchosen1_007 2
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4r - 12 = 8
Need to multiply with 4 using the distribution. And add 12 to both side, will get 4r=20, divide both side by 4 and r=5.
2007-05-01 16:33:45
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answer #6
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answered by K@ti3 2
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first divide throughout by 4 so the equation now becomes
r-3 = 2
add 3 to both sides to make r the subject of the formula
so r=5
2007-05-01 16:27:09
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answer #7
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answered by khadie19 1
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4 x (r - 3) = 8
8/4 = 2
2 + 3 = 5
r = 5
2007-05-01 16:29:44
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answer #8
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answered by Kevin H 7
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4(r-3)=8
r-3=8/4
r-3=2
r=5
or
2^2(r-3)=2^3
so the term r-3 must be 2 to get the same powers on both sides.
r-3=2
or r=5
2007-05-01 16:30:52
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answer #9
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answered by K R 2
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First, do the problem in the parentheses.
(r-3)
4 times what = 8
what=sum of r-3
AS you know r=5
Answer:4(5-3=2)=8
2007-05-01 16:34:33
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answer #10
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answered by betty:] 3
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4(r - 3) = 8
(r - 3) = 8/4
r - 3 = 2
r = 3 + 2
r = 5
2007-05-01 16:27:33
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answer #11
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answered by Rhiaven 2
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