okay..i know that a triangles angles add up to 180, and i need to figure out how much the angles add up to in a quadrilateral and a pentagon. isn't there a trick like multiply the number of angles by 60? but that doesn't work for my problem...any help would be great. thanks!
2007-05-01 16:06:38 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A polygon with n sides can be divided into (n-2) triangles by connecting one vertex to all the others. The angles inside these triangles are all part of the angles of the original polygon, so the sum of the angles is (n-2)×180°.
For instance, you know in a rectangle you have four right angles, so the total is 360°; and indeed the formula above for a quadrilateral (n=4) gives (4-2)×180° = 360°.
2007-05-01 16:09:44 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
Let N be the number of sides. You can construct N-2 interior triangles, so the total of the interior angles is:
180 N - 360
2007-05-01 23:10:44 · answer #2 · answered by Mark H 3 · 0⤊ 0⤋
180(n-2), n is number of angles
2007-05-01 23:13:58 · answer #3 · answered by Anonymous · 0⤊ 0⤋
There is an equation for that, but I cannot recall what that would be.
It is something to do with 180 degrees minus something and the amount of sides.
2007-05-01 23:10:47 · answer #4 · answered by Anonymous · 0⤊ 0⤋