If a cylindrical water tank has a height of 10 and a diameter of 7 calculate the amount of sheet metal needed to create this tank. also Calculate the volume of water that this cylindrical tank will hold
2007-05-01 15:54:44 · 8 answers · asked by bigjoe711 1 in Science & Mathematics ➔ Mathematics
Surface area = 2πrh + 2πr^2
= 2π(35 + 49/4)
= 189/2 π ≈ 296.9 square units.
Volume = πr^2h = π(49/4)(10) = 245/2 π ≈ 384.9 cubic units.
2007-05-01 16:02:56 · answer #1 · answered by Scarlet Manuka 7 · 0⤊ 0⤋
the area of the base of the water tank = pi * r^2 = pi * (7/2)^2 = 12.25pi
perimeter = 2 * pi * r = 7pi
the area of the cylindrical portion of the tank = 7pi * 10 = 70pi
Assume the tank is without cover
total area of sheet metal needed = (12.25+70)pi=82.25pi
volume = base area * height = 12.25pi * 10=122.5pi
2007-05-01 16:44:41 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Assuming that you don't need a particular thickness for the sheet metal in order to create the tank,
circumference of cylinder
= pi x d
= 3.14 x 7 or 22/7 x 7
= 22
amt of sheet metal needed for base (no thickness)
= pi x (radius)^2
= 22/7 x (3.5)^2
= 38.4845
total amt of sheet metal needed for cyclinder with base but no top
= (22 x 10) + 38.4845
= 258.4845
total amt of sheet metal needed for cylinder with base and top
= (22 x 10) + 2(38.4845)
= 296.969
volume
= pi x (radius)^2 x height
= 22/7 x (3.5)^2 x 10
= 384.8451
That's it! =)
2007-05-01 16:05:04 · answer #3 · answered by Rhiaven 2 · 0⤊ 0⤋
94.5pi units squared for the amount of sheet metal or surface area. And the volume is 122.5pi
2007-05-01 16:00:31 · answer #4 · answered by UnknownD 6 · 0⤊ 0⤋
height(h)=10
radius(r)=3.5
therefore,volume=22\7*10*3.5*3.5
=385unit^3
sheet metal=2*22\7*10*3.5 + 22\7*3.5*3.5
=220 + 38.5
=258.5unit^2
2007-05-01 16:07:29 · answer #5 · answered by saurav 2 · 0⤊ 0⤋
amount of sheet metal = surface area = (2 * pi * r^2 ) + (pi*d*10)
SA= 76.93 + 219.8 = 296.73
Volume = pi*r^2*10 = 384.65
2007-05-01 16:04:12 · answer #6 · answered by merz_drm 2 · 0⤊ 0⤋
nope. not a hard question. use cylinder's SA and V formulas
2007-05-01 16:00:22 · answer #7 · answered by Anonymous · 0⤊ 0⤋
piexradius^2xheight so 10x7^2xpie is the volume it will hold
2007-05-01 15:58:39 · answer #8 · answered by Daveman 2 · 0⤊ 0⤋