anyone out there who could possibly help me w/ this math?

Question

use the discriminant to find the types of roots of 3x^2 - x + 5 = 0

Answer 1

For a quadratic equation ax^2 + bx + c = 0, the discriminant is Δ = b^2 - 4ac. If the discriminant is positive, there are two real distinct roots; if it is zero, there is a single repeated real root; if it is negative, there are no real roots (there are two complex conjugate roots, if you've done complex numbers).

In this case a = 3, b = -1 and c = 5, so we get
Δ = (-1)^2 - 4(3)(5) = -59, so there are no real roots.

Answer 2

The roots are (1 + or - the (sqrt of 59) * i)/6