Acid - Base - pH Questions?

Question

1) The conjugate acid of CH3COOH is _________ ??

2) Calculate the pH of 1 x 10^-8 M HCl. (The pH cannot be 8, right?)

Thanks a lot!!!

Answer 1

a. Acetate.
b. Good observation. Plain old water is pH 7. With this, the H+ would be 1.1x10-7 and the pH=
7 - log 1.1.

Answer 2

CH3COOH is acetic acid. are you sure you don't mean conjugate base?
If so the answer is CH3COO-

2) -log [1 x 10^-8] = 8
you cannot have a basic pH so the answer would be extremely close to 7, almost neutral

Answer 3

1) I think you might mean the conjugate base, which is CH3COO-

2) Yep, this is a trick question. You can't have an acid making a basic pH value. You'd have to go to a more exact method of calculation, something not taught in high school or early college. The correct answer is about 6.98 when that more exact calculation is done.

Answer 4

When there is even half as much of a strong base as weak acid you should have a basic solution left over. If they are the same relative strength, adding 10mL of base and 8 of acid should leave you with 2mL of base left in solution. If you still had a pH of 5, you probably tested it or conducted the experiment incorrectly.

Answer 5

1- i think CH3COO_
2- there is some thing wrong with that concentration because acids should have PH< 7

Answer 6

1) CH3COO-

2) HCl------->H+ +Cl-
x x
X^2 =1x10^-8

X=1x10^-4
ph=-log(1x10^-4)
=4
ph of HCL is 4