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Calculate the binding energy per nucleon for the following isotopes

64Zn

MeV/nucleon


7Li

MeV/nucleon

2007-05-01 15:40:14 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

"mproton = 1.007825 u;
mneutron= 1.008665 u;"
E/m = "931.494MeV/u"

64 Zn

BE = (Zmproton + Nmneutron -mnucleus)c^2
(30*1.007825 + 34*1.008665 - 63.9291466)u(931.494 MeV/u) = 559.095 MeV

7Li

(3*1.007825 + 4*1.008665 - 7.016004)u(931.494 MeV/u) = 39.24477 MeV

2007-05-02 09:14:16 · answer #1 · answered by Helmut 7 · 0 0

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