what the the solutions ot this equation
x^2 + 2x + 8 = 4 - 3x
2007-05-01 15:28:14 · 10 answers · asked by heya! 1 in Science & Mathematics ➔ Mathematics
x^2+5x+4=0
(x+4)(x+1)=0
x=-4, -1
2007-05-01 15:31:02 · answer #1 · answered by Anonymous · 0⤊ 0⤋
set it equal to zero:
x^2 + 2x + 3x + 8 - 4 = 0
x^2 + 5x + 4 = 0
find two numbers that add to 5 and multiply to 4:
(4 and 1)
(x + 4)(x + 1) = 0
x + 4 = 0, x = -4
x + 1 = 0, x = -1
2007-05-01 15:31:58 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x^2 + 2x + 8 = 4 - 3x
x^2 + 5x + 4=0
Factor (x +4)(x+1)=0
x +4=0 or x+1 =0 This is because in order 2 get a product of zero you hav 2 multiply by zero
x= -4 or x= -1
2007-05-01 15:33:37 · answer #3 · answered by Yusuf 1 · 0⤊ 0⤋
x = - 4 or - 1. How? :
The equation can be simplified, to become x^2 + 5 x + 4 = 0.
It factorizes: (x + 4)(x + 1) = 0.
Therefore x = - 4 or - 1.
CHECK BY USING ORIGINAL EQUATION (very important)! :
For x = - 4, LHS = 16 - 8 + 8 = 16; RHS = 4 + 12 = 16. Good.
For x = - 1, LHS = 1 - 2 + 8 = 7; RHS = 4 + 3 = 7. That checks!
So the roots x = - 4 and - 1 INDEED satisfy the original equation.
Live long and prosper.
2007-05-01 15:32:04 · answer #4 · answered by Dr Spock 6 · 0⤊ 0⤋
x= -4 or -1
2007-05-01 15:32:03 · answer #5 · answered by Violet15 3 · 0⤊ 0⤋
Combine terms
X^2 +5X + 4 = 0
Factor
(x+4) (x+1) = 0
x= -4
x= -1
2007-05-01 15:34:11 · answer #6 · answered by Matt D 6 · 0⤊ 0⤋
x^2 + 5x + 4 = 0
x = -4 OR x = -1
2007-05-01 15:31:57 · answer #7 · answered by hookemhornsfan1991 2 · 0⤊ 0⤋
x^2+5x+4=0
(x+4)(x+1)=0
x=-4, x=-1
2007-05-01 15:32:30 · answer #8 · answered by trivmtran 2 · 0⤊ 0⤋
x^2+5x+4=0
(x+4)(x+1)=0
x=-4,-1
2007-05-01 15:31:16 · answer #9 · answered by bruinfan 7 · 0⤊ 0⤋
subtract the 4-3x on that side so it becomes x^2-x+4=0 then factor it. if u need me to go on i will but plz do ur own homework
2007-05-01 15:31:54 · answer #10 · answered by Anonymous · 0⤊ 0⤋