2007-05-01 15:19:30 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
well this depends on if you are replacing the cards or not, if you are you would get
1/4*1/4*1/4*1/4.... or in the other words, 1/4^7=1/16384
but if you aren't replacing the cards, then the first card would be 1/4
but the second card would be 12(out of 13 hearts)/51(since you just drew one, so keep multiplying like that and you'll finish.
2007-05-01 15:24:52 · answer #1 · answered by killersdeat0 3 · 0⤊ 0⤋
The odds are (13/52) x (12/51) x (11/50) x (10/49) x (9/48) x (8/47) x (7/46) = 0.000128%
or shall I say almost 1 in 10000 chances
2007-05-01 22:31:04 · answer #2 · answered by WL Tan 2 · 0⤊ 0⤋
We want to choose 7 of 13 hearts, and 0 of 39 other cards, so we have C(13, 7) . C(39, 0) = C(13, 7) = 1716 suitable hands out of C(52, 7) = 133784560 possible. So the probability is 1716 / 133784560 = 33 / 2572780 = 1.28Ã10^-5.
2007-05-01 22:27:37 · answer #3 · answered by Scarlet Manuka 7 · 1⤊ 0⤋
1/4 * 4/17 * 11/50 * 10/49 * 3/16 * 8/47 * 7/46
= 33 out of 2572780 or 33/2572780 or 0.000012826
2007-05-01 22:34:00 · answer #4 · answered by rooster1981 4 · 0⤊ 0⤋
The probabily of getting all these cards as hearts is 1/128. I'm not quite sure though. The chance of getting 1 as a heart is 1/2 so 1/2^7= 1/128
2007-05-01 22:25:33 · answer #5 · answered by UnknownD 6 · 0⤊ 2⤋
your grammer leaves a bit of ambiguity, either the answer is there is no probability that "all" 7 card are hearts
or there is a 25% chance of the 7 card being a heart
ie. 1 in 4 chance.
2007-05-01 22:28:32 · answer #6 · answered by Anonymous · 0⤊ 0⤋
probability is zero since only one out of the four sevens is a heart; 1/52 chance that it is a 7 heart
2007-05-01 22:25:17 · answer #7 · answered by musics_my_world 2 · 0⤊ 3⤋
(13/52)(12/51)(11/50)(10/49)(9/48)(8/47)(7/46)
2007-05-01 22:25:53 · answer #8 · answered by bruinfan 7 · 2⤊ 0⤋
=(1/4) * (12/51) * (11/50) * (10/49) * (9/48) * (8/47) * (7/46)
=(0.25) * (0.235) * (0.22) * (0.204) * (0.188) * (0.170) * (0.152)
=0.000012808877664
2007-05-01 22:26:20 · answer #9 · answered by hookemhornsfan1991 2 · 0⤊ 0⤋